Answer:
The statements that apply are as follows
a). The area of one of its faces is 6 in²
b). The area of one of its faces is 12 in²
c). The volume of the solid is 36 in³
Explanation:
a).
Determine the perimeter of all its faces as shown;
Front and back face dimensions (F1)=6 by 2 inches,
F1 Perimeter=2(6+2)=16 inches
Left and right side face dimensions (F2)=3 by 2 inches
F2 perimeter=2(3+2)=10 inches
Top and bottom face dimensions (F3)=6 by 3 inches
F3 perimeter=2(6+3)=18 inches
b).
Determine the area of all its faces as shown;
F1 dimensions=6 by 2 inches
F 1 area=(6×2)=12 inches²
F2 dimensions=3 by 2 inches
F2 area=(3×2)=6 inches²
F3 dimensions=6 by 3 inches
F3 area=(6×3)=18 inches²
c). Determine the volume of the solid as follows;
Volume=length×width×height
Volume=6×3×2=36 inches³