Question

What is the area of rhombus ABCD ?

Enter your answer in the box. Do not round at
any steps.

Answer 1

it is indeed 24

Explanation:

Answer 2

The area of rhombus = 24

Explanation:

The area of rhombus = base times height

For the given rhombus :

Height = The length of DP

Base = the length of any side of the rhombus as AB

The length ot two point (x₁ , y₁) and (x₂ , y₂) =
`\sqrt{(x_(1) -x_(2) )^2+(y_(1) -y_(2))^2}`

From the given figure:

D = (-5,-2) , P = (-3.8 , 1.6) , A = (1,0) , B = (7 , -2)

DP =
`√((-5-(-3.8))^2+(-2-1.6)^2)` = √14.4

AB =
`√((1-7)^2+(0-(-2))^2)` = √40

So,

The area of rhombus = √14.4 * √40 = √576 = 24