Question

Ch 27 HW Exercise 27.49 13 of 20 Constants A coil with a magnetic moment of 1.42 A⋅m2 is oriented initially with its magnetic moment antiparallel to a uniform magnetic field of magnitude 0.835 T . Part A What is the change in potential energy of the coil when it is rotated 180 ∘ so that its magnetic moment is parallel to the field? UU = nothing J Request Answer Provide Feedback

Answer 1

ΔU = -2.37 J

Step-by-step explanation:

given,

magnetic moment = 1.42 A⋅m²

uniform magnetic field = 0.835 T

Change in potential energy = ?

Potential energy

`U = \vec{\mu}. \vec{B}`

there is scalar product so,

`U = \mu Bcos \theta`

when θ = 0°

`U_1 =\mu B cos 0^0`

`U_1 =\mu B`

when θ = 180°

`U_2 =\mu B cos 180^0`

`U_2 = -\mu B`

Change in potential energy

`\Delta U = U_2 - U_1`

`\Delta U = -\mu B-\mu B`

`\Delta U = -2 \mu B`

`\Delta U = -2* 1.42 * 0.835`

ΔU = -2.37 J