Answer:
seconds
299.0588 meters
Step-by-step explanation:
Given
- speeder has a constant speed,x=15
- officer starts 9 seconds after speeder crosses him and accelerates at 5 from rest
Let assume S as the distance covered by police before he catches him
let T be the time taken by him to do so

Therefore S
(since initial velocity=0)
This same distance is covered by the speeder in time T+9 as officer starts after pausing 9 seconds
Therefore S

equating both the equations

Solving the quadratic we get
T=3+3
or T=3-3
(not possible as T cannot be less than 0)
So it takes 3+3
seconds for the officer to catch the speeder
⇒Distance covered
=299.0588 m