Answer:
The length of AC to the nearest hundredth = 8.06 units.
Explanation:
In the given triangle ABC
CB = 7 units
AB = 4 units
Let AC = h units
Now, using PYTHAGORAS THEOREM in a right angled triangle:
![(BASE)^2 + (PERPENDICULAR)^2 = (HYPOTENUSE)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/svecqbhtjg2oes1ww20osnqbvnjqclo9o1.png)
⇒
![(7)^2 + (4)^4 = h^2\\\implies h^2 = 49 + 16 = 65\\or, h = \sqrt(65) = 8.0622](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pfsft7geuf0s8rq12h7mtcwt3a54et74pp.png)
⇒The hypotenuse AC of the given triangle is 8.0622 units.
Rounding off to the nearest hundredth, h = 8.06 units.
Hence, the length of AC = 8.06 units.