Answer:
The genotype of the colored plant is A/a C/C R/r.
Step-by-step explanation:
The genotype A/-; C/-; R/- is colored; all others are colorless.
A colored plant (A/?; C/?;R/?) is crossed with three tester.
- We know the colored plant can't be homozygous recessive for any gene.
- When a homozygous dominant genotype is crossed with a homozygous recessive (BB x bb), all the seeds will have one dominant allele (Bb) and therefore color.
- When a heterozygous genotype for a single gene (Bb) is crossed with a homozygous recessive (bb), 50% of the seeds will be Bb (colored).
1. The cross A/- C/- R/- X a/a c/c R/R produces 50% colored seeds.
All the seeds will have the R allele, so the original plant is heterozygous for either A/a or C/c.
2. The cross A/- C/- R/- X A/A c/c r/r produces 50% colored seeds.
All the seeds will have the A allele, so the original plant is heterozygous for either C/c or R/r.
3. The cross A/- C/- R/- X a/a C/C r/r produces 25% colored seeds.
All the seeds will have the C allele, so the original plant is heterozygous for both A/a and R/r (the offspring would be 1/2 Aa x 1 CC x 1/2 Rr ---> 1/4 colored seeds).
The genotype of the colored plant is therefore A/a C/C R/r.