Question

In the first step of the addition reaction with HBr, the pi electrons of the double bond react with the hydrogen ion, H+, producing a carbocation. The hydrogen atom that forms a new carbon-hydrogen bond as a result is highlighted in red. Sort the carbocation intermediates as major carbocations or their corresponding minor intermediates for each of the given reactions. Consider a carbocation minor even if it is highly unstable and may be virtually nonexistant.

Answer 1

See the figure

Step-by-step explanation:

In this case, we have to take into account the stability of the carbocations:

Terciary>Secundary>>Primary.

In other words, is we have the most substituted carbocation we will have more stability. Therefore in the carbocation formation, the charge would go in the most substituted carbon of the double bond for each case.