Question

The Mariana trench is located in the Pacific Ocean at a depth of about 11 000 m below the surface of the water. The density of seawater is 1025 kg/m3. (a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.184 m)? (b) For comparison, determine the weight of a jetliner whose mass is 3.96 × 105 kg.

Answer 1

a.
`F=11.7416x10^6 N`

b.
`W=3.8808x10^6N`

Step-by-step explanation:

Pressure is find by:

`P=P_(out)-P_(in)`

`P_(in)=101325 N/m^2`

`P_(out)=p*g*d=1025 kg/m^3*9.8m/s^2*11000m`

`P_(out)=1.10495x10^8 N/m^2`

`P=(1.10495x10^8 -0.101325x10^6)N/m^2`

`P=110.3936x10^6 N/m^2`

a.

`F=P*A`

`A=\pi*r^2=\pi*(0.184m)^2=0.106m^2`

`F=110.3936x10^6 N/m^2*0.106m^2`

`F=11.7416x10^6 N`

b.

`W=m*g`

`W=3.96x10^5kg*9.8 m/s^2`

`W=3.8808x10^6N`