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A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity afterward? PLEASE HELP

2 Answers

2 votes

Answer:

.345

Step-by-step explanation:

User FreewheelNat
by
4.8k points
1 vote

Answer:

2.877 m/s

Step-by-step explanation:

According to the laws of conservation of linear momentum,

the momentum of the moving objects before impact is equal to the momentum of the objects after impact (Assuming no external forces were applied)

Let both players are tackled and moving in V velocity

  • M and m - masses of the players
  • U and u - velocities of them respectively (both velocities are towards east direction )

momentum before impact = momentum after impact

→MU + →mu = →(M+ m )v

91.5 * 2.73 + 63.5 * 3.09 = (91.5 + 63.5) * V

→V = 2.877 m/s (To East)

User Kayahr
by
4.8k points