Question

A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity afterward? PLEASE HELP

Answer 1

Step-by-step explanation:

the top of me is right its 3.47 so the top of me is smart

Answer 2

Their velocity afterwards =
`3.47\ ms^(-1)`

Step-by-step explanation:

Mass of Player 1 =
`m_1`=
`91.5\ kg`

Mass of Player 2 =
`m_2`=
`63.5\ kg`

Velocity of Player 1 moving east =
`3.73\ ms^(-1)`

Velocity of Player 2 moving left =
`3.09\ ms^(-1)`

By law of conservation of momentum:

`m_1v_1+m_2v_2=(m_1+m_2)v`

Here
`v` represents the velocity of tangled players.

Plugging in values in the equation.

`(91.5* 3.73)+(63.5* 3.09)=(91.5+63.5)v`

`341.295+196.215=(155)* v`

`537.51=(155)* v`

Dividing both sides by 155.

`(537.51)/(155)=((155)* v)/(155)`

∴
`v=3.467\approx 3.47\ ms^(-1)`

Their velocity afterwards =
`3.47\ ms^(-1)`