Question

In a biathlon , jackson cycled 9 miles in 3/4 of an hour in the first event. He than ran, on average, 7 miles per hour slower in the second event, which took him 1 1/2 hours. What is the distance that jackson ran in the second event ?

Answer 1

7 1/2

Explanation:

because the dude under me was not thinking about the people who don't know what 7.5 mean it is 7 and .5 is half so 7 1/2

Answer 2

7.5 miles

Explanation:

Given

• In cycling,He covered 9 miles in
  `(3)/(4)` hours,Therefore his avg cycling speed, u
  `=(Distance)/(Time) =(9)/((3)/(4) ) =12(miles)/(hour)`
• In second event, It took him
  `1(1)/(2) =(3)/(2)`hours to complete,And his avg speed,v is 7
  `(miles)/(hour)` slower than in previous event

⇒v= u-7

v= 12-7

v=5

Distance covered in 1st event
`=9miles`

Distance covered in 2nd event
`=Speed* Time= 5* (3)/(2) =7.5miles`