Question

When an object is placed just outside the focal length of a concave mirror, the image is

O smaller than the object and virtual.
O larger than the object and virtual.
O smaller than the object and real.
O smaller than the object and reversed. larger than the object and real

Answer 1

O larger than the object and real

Step-by-step explanation:

As we know by the formula of mirror

`(1)/(d_i) + (1)/(d_o) = (1)/(f)`

here we know that

`d_o = (f_o + x)`

so we have

`(1)/(d_i) = (1)/(f_o) - (1)/(f_o + x)`

so we have

`d_i = ((f_o)(f_o + x))/(x)`

so magnification is given as

`M = -(d_i)/(d_o)`

`M = - (f_o)/(x)`

so here we have

`|M| > 1`

so image will be larger than object and real