Question

A sled and rider with a combined mass of 70 kg are at the top of a hill of height 9 m above the level ground below. The sled is given a push providing an initial kinetic energy of 1200 J at the top of the hill. What will be the kinetic energy of the sled and rider at the bottom of the hill, if friction can be ignored?

Answer 1

`K_p=6174J`

Step-by-step explanation:

Given:

`m=70kg`,
`m=9m`,
`K_E=70kg`

`K_E=(1)/(2)*m*v^2`

`1200J=(1)/(2)*70kg*v^2`

`v=5.8m/s`

To determine the kinetic energy at the bottom is:

`K_p=m*g*h`

`K_p=70kg*9.8m/s^2*9m`

`K_p=6174J`