Answer:
The speed of jet in still air is 1060 miles per hour And
The speed of jet stream is 160 miles per hour .
Explanation:
Given as ;
The Distance of jet against jet stream is 8100 miles
The Time taken by jet against jet stream is 9 hours
The Distance of jet with jet stream is 6100 miles
The Time taken by jet with jet stream is 5 hours
Let the speed of jet in still air = x mph
And The speed of jet stream = y mph
Now, Speed =
![(Distance)/(Time)](https://img.qammunity.org/2020/formulas/mathematics/college/celd9v81qwv4b5nwmu15b28jymknh7z8l5.png)
So, According to question
The speed of jet against jet stream =
![(Distance of jet against jet stream)/(Time taken by jet against jet stream)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/41dqfv339g4gvdr1ytd3d4eazcwtamoyyb.png)
I.e x - y =
![(8100)/(9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3y8vroims9x0mcvx69tcjxe9yzf147qb4k.png)
Or , x - y = 900 mph .....A
Again ,
The speed of jet with jet stream =
![(Distance of jet with jet stream)/(Time taken by jet with jet stream)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ibdo7fmnbvljfqofzqnlbbc7ourdhk27o5.png)
I.e x + y =
![(6100)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g7nd3pw3pgrnruqxtt6ogl0f1g4sa3k4zl.png)
Or , x + y = 1220 mph .......B
Solve equation A and B
so, ( x + y ) + ( x - y ) = 1220 + 900
or, 2 x = 2120 mph
∴ x =
= 1060 miles per hour
And From eq A
x - y = 900 mph
y = x - 900
Or, y = 1060 - 900 = 160 miles per hour
Hence The speed of jet in still air is 1060 miles per hour And The speed of jet stream is 160 miles per hour . Answer