Question

What is the percentage of a mixture containing 2.5lb of salt and 4 gallons of water

Answer 1

Percentage of mixture=
`7.5\%`

Explanation:

Salt content in pounds=
`2.5` lb

`1\ lb = 0.12\ gal`

Therefore salt content in gallons =
`2.5* 0.12 = 0.3` gal

Water content in mixture =
`4` gal

Percentage of mixture=
`(\ Salt\ Content)/(Water\ Content)* 100 = (0.3)/(4)* 100=(30)/(4)=7.5\%`