Question

Theequationoflineqis y + 3 = -6 5 ( x − 5 ) . Line r , whichisperpendiculartoline q , includesthepoint (3, 4) . What istheequationofline r ?

Answer 1

y -4 = 5/6(x -3)

Explanation:

The slope of a perpendicular line is the negative reciprocal of the slope of the given line. The equation of the given line is in a form that looks like point-slope form:

y -k = m(x -h) . . . . . . with point (h, k) = (5, -3) and slope m=-6/5

The slope of the perpendicular line will be ...

m = -1/(-6/5) = 5/6

The perpendicular line goes through point (h, k) = (3, 4), so its equation in point-slope form will be ...

y -4 = 5/6(x -3)