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5 votes
Can I please have help, I don't know how to solve this.

3741 = P(P-1) over 2

User Ecarrizo
by
4.9k points

1 Answer

5 votes

Answer:

The values of P are -87 or 86.

Explanation:

Given:


3741=(P(P-1))/(2)

Multiply by 2 on both the sides. This gives,


3741* 2=(P(P-1))/(2)* 2\\7482=P(P-1)

Now, use distribution property.


7482=P* P - P* 1\7482=P^2-P

Now, add -7482 on both sides,


P^2-P-7482=0

This is a quadratic equation of the form
ax^2+bx+c=0 which can be solved using quadratic formula with
a=1,b=-1,c=-7482


P=(-b\pm √(b^2-4ac))/(2a)\\P=(-1\pm√((-1)^2-4(1)(-7482)))/(2(1))\\P=(-1\pm√(1+29928))/(2)\\P=(-1\pm√(29929))/(2)\\P=(-1-173)/(2)\textrm{ or }P=(-1+173)/(2)\\P=(-174)/(2)\textrm{ or }P=(172)/(2)\\P=-87\textrm{ or }P=86

Therefore, the values of P are -87 or 86

User Szhem
by
4.9k points
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