Question

Graph the line that contains the point (-5,-3) and had a slope of -2

Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

`y = mx + b`

Where:

m: Is the slope

b: Is the cut-off point with the y axis

According to the data of the statement we have to:

`m = -2`

Then, the equation is of the form:

`y = -2x + b`

We substitute the point
`(x, y): (- 5, -3)`and find "b":

`-3 = -2 (-5) + b\\-3 = 10 + b\\-3-10 = b\\b = -13`

Finally, the equation is:

`y = -2x-13`

To graph we place the points
`(-5, -3)`and
`(0, -13)` on the coordinate axis and join the points by a line.

ANswer:

`y = -2x-13`

The graphic is attached.