Question

Suppose you apply a flame to heat 1 liter of water and its temperature rises by 3 C. If you apply the same flame for the same length of time to 3 liter of water, by now how much does its temperature rise

Answer 1

Answer:1
`^(0)C`

Step-by-step explanation:

Let the heat given by flame be
`h`.

Let
`m_(1)` be the mass of water in case 1.

Let
`m_(2)` be the mass of water in case 2.

Let Δ
`T_(1)` be the temperature difference in case 1.

Let Δ
`T_(2)` be the temperature difference in case 2.

Let
`V_(1)` be the volume of water in case 1.

Let
`V_(2)` be the volume of water in case 2.

Let
`d` be the density of water.

Let
`s` be the specific heat of water.

Given,

`V_(1)=1L\\V_(2)=3L\\`

Δ
`T_(1)=3^(0)C`

Since the same heat is given to water in both the cases,

`h=m_(1)s`Δ
`T_(1)`

`h=m_(2)s`Δ
`T_(2)`

So,
`m_(1)s`Δ
`T_(1)`=
`m_(2)s`Δ
`T_(2)`

Since mass is product of volume an density,

`V_(1)ds`Δ
`T_(1)`=
`V_(2)ds`Δ
`T_(2)`

`1* d* s* 3=3* d* s*`Δ
`T_(2)`

So,Δ
`T_(2)=1^(0)C`