Question

A container has a volume of 5.43 L and a pressure of 7.97 atm. If the pressure changes to 2.32

atm, what is the container's new volume?​

Answer 1

18.65 L

Step-by-step explanation:

We are given;

• Initial volume of the container, V1 as 5.43 L
• Initial pressure of the container, P1 as 7.97 atm
• New pressure, P2 is 2.32 atm

We are required to calculate the container's new volume;

We are going to use Boyle's law

• According to Boyle's law the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant absolute temperature.
• That is;
  `P\alpha (1)/(V)`

• At varying pressure and volume at constant temperature, k is the constant.
• Therefore;
  `P1V1=P2V2`

Rearranging the formula;

`V2=(P1V1)/(P2)`

`V2=((7.97atm)(5.43L))/(2.32atm)`

`V2=18.654`

Therefore, the new volume will be 18.65 L