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A 6.7-kg box is being lifted by means of a light rope that is threaded through a single, light, frictionless pulley that is attached to the ceiling. (a) If the box is being lifted at a constant speed of 2.0 m/s, what is the power delivered by the person pulling on the rope? kW (b) If the box is lifted, at constant acceleration, from rest on the floor to a height of 1.2 m above the floor in 0.42 s, what average power is delivered by the person pulling on the rope?

User Makro
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1 Answer

5 votes

Answer:

a.
P=131.32 W

b.
P=447.95W

Step-by-step explanation:

a).


v=2.0 m/s


P=m*g*v


P=6.7kg*9.8m/s^2*2.0m/s=131.32 (kg*m^2)/(s^3)


P=131.32 W

b).


h=(1)/(2)*a*t^2


a=(2*h)/(t^2)=(2*1.2m)/((0.42s)^2)


a=13.6 m/s^2


F=m*g+m*a


F=6.7kg*9.8m/s^2+6.7*13.6m/s^2


P=(F*d)/(t)


P=(188.136kg*m^2/s^2)/(0.42s)


P=447.95W

User Andres Kull
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