Question

You want to wind a solenoid that is 3.5 cm in diameter, is 23 cm long, and will have a magnetic field of 0.0250 T when a current of 3.0 A is in the wire that makes up the solenoid. 1) What total length of wire do you need?

Answer 1

L'=167.7 m

Step-by-step explanation:

Given that

d= 3.5 cm

L= 23 cm

B=0.025 T

I= 3 A

As we know that magnetic field in solenoid given as

`B=(\mu _oNI)/(L)`

N=Number of turns

L=Length

B=Magnetic filed

I=Current

`N=(BL)/(\mu _oI)`

Now by putting the all values

`N=(BL)/(\mu _oI)`

`N=(0.025* 0.23)/(4\pi * 10^(-7)* 3)`

N=1525.23 turns = 1526 turns

Total length L'=Nπd

L'=1526 x 3.14 x 0.035

L'=167.7 m