1 Answer

Akber Choudhry · Answer 1 · 2020-06-17T01:47:57+0000

For this case we have that the area of the figure is given by the area of the side square
$8 \ in$ minus the area of the small rectangle.

By definition, the area of a square is given by:

A = l ^ 2

Where:

l: It's the side of the square

In this case,
$l = 8 \ in$

The area of a rectangle is given by:

A = a * b

Where:

a and b are the sides of the rectangle

In this case,
$a = 4 \ in$ and
$b = 3 \ in$

So:

$A_ {t} = 8 ^ 2-4 * 3\\A_ {t} = 64-12\\A_ {t} = 52$

Thus, the area of the figure is
$52 \ in ^ 2$

Answer:

$52 \ in ^ 2$

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