Question

You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of

reference he has a speed of 3 m/s to the south. What is the velocity of the man from the frame of
reference of a stationary observer? (2 points)

Answer 1

1 m/s south

Step-by-step explanation:

you're walking 2 m/s north and a man is approaching you at a 3 m/s south velocity, this man is actually walking 3 - 2 = 1 m/s south to a stationary observer; because from your frame of reference, he's walking 3 m/s approaching you, but don't forget your direction is opposite to his. it would be 5 m/s only if it were for you and the man walking in the same direction.

Answer 2

The velocity of the man from the frame of reference of a stationary observer is, V₂ = 5 m/s

Step-by-step explanation:

Given,

Your velocity, V₁ = 2 m/

The velocity of the person, V₂ =?

The velocity of the person relative to you, V₂₁ = 3 m/s

According to the relative velocity of two

V₂₁ = V₂ -V₁

∴ V₂ = V₂₁ + V₁

On substitution

V₂ = 3 + 2

= 5 m/s

Hence, the velocity of the man from the frame of reference of a stationary observe is, V₂ = 5 m/s