Question

An electrical heater is used to supply 245.0 J of energy to a 15.0 g sample of aluminum, originally at 310.0 K. Determine the final temperature in degrees Kelvin. (the specific heat capacity for aluminum is 24.35 Jmol-1K-1)

Answer 1

`T_f=328.1 K`

Step-by-step explanation:

To determine the final temperature of the sample, we use the specific heat formular as follows:

`Q=mCp(T_f-T_0)\\T_f=(Q)/(mCp) +T_(0)\\mol Al= (15g)/(26.98gmol^(-1))=0.555 mol\\T_f=(245.0J)/(0.555mol*24.35Jmol^(-1)K^(-1)) +310.0K\\T_f=328.1 K`

Finally, the temperature of the aluminium sample has raised 18 K.