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Answer:

The equation of line in point slop from is

y - 8 = -
(2)/(3) × (x + 3 )

Explanation:

Given slop-intercept line equation as :

y = -
(2)/(3)x + 6

I.e y = mx + c

and point the line is passing through ( -3 , 8 )

So, point slop form of this line is

y - y_1 = m × (x - x_1)

Slop of above line is -
(2)/(3)

Now line passes through given points and this slop is

y - 8 = -
(2)/(3) × (x + 3 )

Hence the equation of line in point slop from is

y - 8 = -
(2)/(3) × (x + 3 )
Answer

User Anejah Daniels
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