Question

A charge of 3 nC is uniformly distributed around a ring of radius 10 cm that has its center at the origin and its axis along the x axis. A point charge of 1 nC is located at x = 2.5 m. Find the work required to move the point charge to the origin. Hint: The electric field on the axis was calculated in class (see Example 3 in the the slides for Lecture 16).

Answer 1

`W=2.592*10^(-7) J`

Step-by-step explanation:

GIVEN DATA:

Charge 3 nC

Radius of ring is 10 cm

A point charge 1 nC

Distance of point charge is 2.5 m

We know that voltage is calculated as

`V(0) =(KQ)/(r)`

`=((9*10^(-9))(3*10^(-9)))/(0.1)`

V = 270 V

At x = 2.5m

`r = √((0.1^2+2.5^2))`

r = 1.581 m

`V(2) = ((9*10^9)(3*10^(-9)))/(1.581)`

V(2) = 10.801 V

Work done is calculated as

W= q(dV)

`W = (1*10^(-9))(270 - 10.80)`

`W=2.592*10^(-7) J`