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Write a quadratic equation that has integer coefficients and has solutions 4 and 7

1 Answer

6 votes

Answer:

The quadratic equation is:
x^2-11x+28=0\\

Explanation:

The quadratic equation with given solutions
a and
b can be written as:


(x-a)(x-b)=0

Given:

Solutions are 4 and 7.

The quadratic equation can be written as:


(x-4)(x-7)=0\\

We simplify it further to get it in standard form.

Using FOIL(Firsts Outsides Insides Lasts )


(x* x)+(x*(-7))+((-4)* x)+(-4*(-7))=0\\\\x^2-7x-4x+28=0\\

Combining like terms:


x^2-11x+28=0\\

The quadratic equation is:
x^2-11x+28=0\\

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