1 Answer

Elysee · Answer 1 · 2020-06-12T19:55:40+0000

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the statement we have to:

$m = \frac {1} {2}$

So, the equation is of the form:

$y = \frac {1} {2} x + b$

We substitute the given point and find "b":

$-7 = \frac {1} {2} (2) + b\\-7 = 1 + b\\-7-1 = b\\b = -8$

Finally, the equation is:

$y = \frac {1} {2} x-8$

By definition, the standard form of the equation of the line is:

ax + by = c

Then, we manipulate the equation algebraically:

$y = \frac {1} {2} x-8\\y + 8 = \frac {1} {2} x\\2 (y + 8) = x\\2y + 16 = x\\x-2y = 16$

Answer:

The equation in the standard form is:

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