Answer: N(20, 4) distribution.
Explanation:
Normal approximation to Binomial :
The normal approximation is used for binomial distribution having parameters n and p as
![\mu=np\\\\ \sigma=√(np(1-p))](https://img.qammunity.org/2020/formulas/mathematics/college/zurk7jke3i8769xc7rukn807eokgb1z7ub.png)
if x is the random variable then x has
.
Given : As part of a promotion for a new type of cracker, free trial samples are offered to shoppers in a local supermarket.
The probability that a shopper will buy a packet of crackers after tasting the free sample : p=0.20.
Different shoppers can be regarded as independent trials.
if X is the number among the next 100 shoppers who buy a packet of crackers after tasting a free sample.
Then, Mean and standard deviation for x will be :
![\mu=(100)(0.20)=20\\\\ \sigma=√(20(1-0.20))=√(16)=4](https://img.qammunity.org/2020/formulas/mathematics/college/4aio0b4odvq754l8w429uz7hn0avzrdaup.png)
i.e. X has approximately an N(20, 4) distribution.