Question

A car starts from rest and travels for 5.8 s with a uniform acceleration of 1.6 m/s² in the negative direction. What is the final velocity of the car? Answer in units of m/s.How far does the car travel in this time interval?

Answer 1

Final velocity of the car will be -9.28 m/sec

Step-by-step explanation:

We have given that the car starts from the rest so initial velocity of the car u = 0 m /sec

Acceleration of the car
`a=1.6m/sec^2` in negative direction so acceleration will be
`a=-1.6m/sec^2`

From first equation of motion we know that

v = u+at

So
`v=0+(-1.6)* 5.8=-9.28m/sec`

So final velocity will be -9.28 m/sec