Question

Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the fourth-order bright band is 13.5 ◦ . If the screen is 154 cm from the double-slit, how far apart is this bright band from the central peak? Answer in cm.

Answer 1

Answer:0.369 m

Explanation:

Given

Distance between slit and screen is
`D=154 cm`

Wavelength
`\lambda =348 nm`

Angle between zeroth order bright fringe and Fourth-order bright fringe is
`\theta =13.5^(\circ)`

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

`y_n=(nD\lambda )/(d)`

Also
`\tan \theta =(y_4)/(D)`

`y_4=\tan (13.5)\cdot 1.54`

`y_4=0.24* 1.54`

`y_4=0.369 m`