Question

A spring has a force constant of 570.8 N/m. Find the potential energy stored in the spring when the spring is

Answer 1

Given that,

The force constant of a spring, k = 570.8 N/m

It is stretched 4.12 cm from the equilibrium.

To find,

The potential energy stored in the spring.

Solution,

The potential energy stored in the spring is given by the formula as follows :

`E=(1)/(2)kx^2`

Put all the given values,

`E=(1)/(2)* 570.8 * (4.12* 10^(-2))^2\\\\E=0.484 J`

So, the required potential energy is 0.484 J.