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Michael has 3 quarters, 2 dimes, and 3 nickels in his

pocket. He randomly draws two coins from his pocket,
one at a time, and they are both dimes. He says the
probability of that occurring is because 2 of the 8
coins are dimes. Is he correct? Explain.

User Tomsgd
by
4.0k points

2 Answers

7 votes

Answer:

No. Choosing two dimes are dependent events. The probability of choosing the first dime is 14 and the probability of choosing the second dime is 17 . The probability that both coins are dimes is (14)(17) = 128.

Hope this helps and the other guys is right :)

Explanation:

User Mark Comix
by
4.3k points
14 votes

My Answer:

The events are dependent.

  • The size of the original sample space is 8. It changes to 7 after the first dime is chosen.

  • The probability of picking the first dime is 2/8.

  • The probability of picking the second dime is 1/7

To find the probability of the compound event, multiply the probabilities.

I got it correct, on edge 2020/2021

User Selvaraj
by
4.3k points