Question

4. An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5

m/s? over a distance of 20 m. What is its new velocity?

Answer 1

11.9 m/s

*But if you need the answer with sig figs it should be 10m/s (1sf) or 12m/s (2sf)

Step-by-step explanation:

`{vf}^(2) - {vi}^(2) = 2ad`

`{vf}^(2) = 2ad + {vi}^(2)`

`{vf}^(2) = 2 * 1.5 * 20 + {9}^(2)`

`{vf}^(2) = 60 + 81`

`{vf}^(2) = 141`

`vf = √(141)`

`vf = 11.874`

best answer if it worked