Answer:
It is
degrees Fahrenheit when the crickets are chirping
times a minute.
Variables
and
![y = Degrees](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ytrbl62s58c14f1gjrehhy4wjkufjtw5wj.png)
y-intercept
![= 38.24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gp9ay5k51vxf8s350s08c1cy9ulqf592kb.png)
slope
Explanation:
As the chirps are
times per minute for
degrees Fahrenheit we will consider it in
.
Now when the chirps are
times and temperature is
degrees we consider it
.
To find the slope we can use point-slope formula.
Where
is the slope and
![m=(y_2-y_1)/(x_2-x_1) =(80-68)/(172-124)= 0.24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/43p72otoel9crwzven067nb6yad7cga0r0.png)
To find y-intercept we will plug out the value of slope in
choosing point
.
So
![b=y-m(x) =68-124(0.24) =68-29.76=38.24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/l3gcot4a904kmvh7gy5cwexab1uavnfbnn.png)
And the equation is
![y=0.24(x)+b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b17gcxf0e7lctxfapgvykhxjxcpk71dqns.png)
To calculate temperature for
chirpings we have to plug
and
in our above equation which is in form of
degrees Fahrenheit.
Finally we have :
Temperature
degrees Fahrenheit.
With variables
and
![y = Degrees](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ytrbl62s58c14f1gjrehhy4wjkufjtw5wj.png)
y-intercept
and
slope