Question

Find the perimeter of a rectangle
L= 2x^2+3x+1
W= x+3

Answer 1

The perimeter of the rectangle is
`P(x) = (4x^(2)  + 8x + 8)`

Explanation:

Length of the rectangle =
`2x^(2)   +3x + 1`

Width of the rectangle = x + 3

The Perimeter of the Rectangle = 2 (Length + Width)

So, here the perimeter =
`2((2x^(2)  + 3x +1 )+(x+3))  = 2 (2x^(2)  + 3x + 1 + x +3)\\= 2(2x^(2)  + 4x+4) = 4x^(2)  + 8x + 8`

Hence,the perimeter of the rectangle is
`P(x) = (4x^(2)  + 8x + 8)`