Answer:
Status: Open
Answers: 3
Explanation:
Mar 10, 2019 · x = (2/5)y + 2 5x + 3z = -5 5[(2/5)y + 2] + 3z = -5 2y + 10 + 3z = -5 2y + 3z = -15 Since this is the same as the second equation if you multiply both halves by -1, we essentially have two unknowns with one equation which has infinite solutions. Therefore the set of …