Question

2c4H10 +13O2 —>8CO2+10H2O to find how many moles of oxygen would react with 4.3 mol C4H10

Answer 1

`\large\boxed{\text{28 mol of O$_(2)$}}`

Step-by-step explanation:

2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

n/mol: 4.3

13 mol of O₂ react with 2 mol of 2C₄H₁₀

`\text{Moles of O}_(2) = \text{4.3 mol C$_(4)$H$_(10)$} * \frac{\text{13 mol O}_(2)}{\text{2 mol C$_(4)$H$_(10)$}} = \textbf{28 mol O}_(2)\\\\\text{The reaction requires $\large\boxed{\textbf{28 mol of O$_(2)$}}$}`