148k views
3 votes
Complete the problem to represent the situation given by the equation 0.40e + 10 + 15 = 0.20e + 5 + 25. At one store a trophy costs $15, initial engraving set-up cost $0.40 , and engraving costs $0.20 per letter. At another store, the same trophy costs $25 , initial engraving set-up costs $5, and engraving costs $10 per letter. How many letters, e, must be engraved for the costs to be the same?

1 Answer

5 votes

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Explanation:

Since we have given that


0.4e+10+15=0.20e+5+25

We need to find the number of letters.


0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=(25)/(0.2)\\\\e=125

Hence, the number of letters that must be engraved for the costs to be the same is 125.

User Alessandro Pezzato
by
7.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.