Question

For each case below, determine the terminal speed of the rod. In each case, the length of the rod is 0.240 m. Part (a) uses parameters that can be set with the animation sliders, and you can use the animation to verify the results of your calculation (the value of the terminal velocity is given in a readout). Part (b) uses parameter values outside the range of the animation.

a. Let the applied force be 0.05 N, the resistance be 10 Ohm, and the magnetic field be 1 T. v_t = _____ m/s.
b. Let the applied force be 2.72 N, the resistance be 10 Ohm, and the magnetic field be 1 T. v_t = _____ m/s.

Answer 1

(a) 8.68 m/sec

(b) 472.22 m/sec

Step-by-step explanation:

We have given that length of the rod l = 0.240 m

(a) We have given force F = 0.05 N

Resistance R = 10 ohm

Magnetic field B = 1 Tesla

We have to find the terminal velocity

We know that terminal velocity is given by

`v_t=(F R)/(B^2l^2)` ,here F is force, R is resistance B is magnetic field and l is length of the rod

So
`v_t=(0.05*  10)/(1^2* 0.240^2)=8.68m/sec`

(b) Applied force F = 2.72 N

Resistance R = 10 ohm

Magnetic field B = 1 Tesla

We know that terminal velocity is given by

`v_t=(F R)/(B^2l^2)` ,here F is force, R is resistance B is magnetic field and l is length of the rod

So
`v_t=(2.72*  10)/(1^2* 0.240^2)=472.22m/sec`