Question

A bicyclist is traveling at +25 m/s when he begins to decelerate at -4 m/s2. How fast is he traveling after 5 seconds?

Answer 1

The bicyclist goes at 5 m/s

Step-by-step explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time.

The equation that rules the change of velocities is:

`v_f=v_o+at`

Where:

a = acceleration

vo = initial speed

vf = final speed

t = time

It's given a bicyclist is traveling at v0=+25 m/s and decelerates at
`a=-4\ m/s^2`. We are required to calculate the speed after t=5 seconds.

Applying the formula:

`v_f=25+(-4)*5`

`v_f=25-20=5`

`v_f=5\ m/s`

The bicyclist goes at 5 m/s