Question

Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the other pulls in the same direction with a force of 360 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor?

Answer 1

Answer:0.27

Step-by-step explanation:

Given

One worker Pushes with force
`F_1=430 N`

other Pulls it with a rope of rope
`F_2=360 N`

mass of crate
`m=290 kg`

both forces are horizontal and crate slides with a constant speed

Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it

`f_r=F_1+F_2`

where
`f_r` is the friction force

`f_r=430+360`

`f_r=790 N`

`f_r=\mu N`

where
`\mu`is the coefficient of static friction

`N=mg`

`790=\mu 29\cdot 9.8`

`\mu =0.27`