Find the dy/dx y = sec³(3x)

Mandar Pandit asked Jun 1, 2023

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34 votes

Find the dy/dx

y = sec³(3x)

Mandar Pandit asked Jun 1, 2023

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7 votes

y = sec³(3x)

dy/dx = d (sec 3x)³/dx . d (sec 3x)/dx . d(3x)/dx

y' = dy/dx = 3(sec² 3x) . (tan² 3x) . 3

y' = 9 sec² (3x) tan² (3x)

Hence, option C is correct!

Hope it helps..

Kartik Rokde answered Jun 6, 2023

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