Question

An object with a mass of 3.0kg has a force of 9.0 newtons applied to it. What is the resulting acceleration of

the object?

Answer 1

The acceleration is:
`a=3 (m)/(s^2)`

Step-by-step explanation:

To answer this, we need to recall Newton's Second Law of motion, that states that an object of mass m would accelerate (change its state of uniform motion) proportional to the force (F) that is applied , and exemplified by the following equation:

`F=m\,a`

From here, and using the given values for mass (m = 3 kg) and force (F = 9 N), we can derive the value of the acceleration as shown below (notice that since all quantities are given in SI units, the resulting acceleration will also be in Si units (
`(m)/(s^2)`):

`F=m\,a\\9\,N=3\,kg\,a\\a=(9)/(3) (m)/(s^2) \\a=3 (m)/(s^2)`