Question

A stone is thrown horizontally at a speed of 19.4m/s from the top of a cliff 19.4m high. What is the horizontal distance from the base of the cliff where the stone lands?

Answer 1

38.218 m

Step-by-step explanation:

Horizontal projectile motion is there.(graph)

applying motion equations for downward motion

(only a horizontal velocity is there. stone is subjected to the gravity )

Sv = height

u = initial velocity

t= time taken

`S_v=ut+(1)/(2)*at^(2)  \\19.4=0+(1)/(2)*10*t^(2)  \\t=1.97 s`

for horizontal motion

Sh= horizontall distance

`S_h=ut\\s=19.4*1.97\\s=38.218 m`