Question

before colliding, the momentum of block A is +25.0 kg*m/s, and block b is +35.0 kg*m/s. after, block a has a momentum +60.0 kg*m/s. what is the momentum of block b afterwards?

Answer 1

0 kg*m/s

Step-by-step explanation:

Answer 2

0 kg*m/s

Step-by-step explanation:

The law of conservation of momentum states that the total momentum of a closed system is conserved. It means that the sum of momentum of individual objects in a closed system remains the same throughout.

For this system, the total momentum of the system before collision is +25+35= +60;

After collision:

60 = momentum of block A + momentum of block B

60=60+x, where x is the momentum of block B. Evaluate x.