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What is the additive inverse of the complex number -8 + 3i?

2 Answers

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The additive inverse of a number x is a number y such that


x+y=0

From this definition, we can derive


y=-x

So, to get the additive inverse of a number, you simply have to switch its signs.

Since complex numbers are made of two pieces (real and complex parts), you'll have to switch both signs:


z=-8+3i \implies -z = 8-3i

In fact, if you try to sum them, you have


(-8+3i)+(8-3i)=(-8+8)+(3i-3i)=0

User Dgil
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2 votes

Answer:

8 - 3i

Explanation:

The additive inverse is what you add to a number to get zero.

Thus adding 8 - 3i to - 8 + 3i gives

- 8 + 3i + 8 - 3i = 0

Additive inverse is 8 - 3i

User Abubakar Mehmood
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