Question

A spring with a spring constant of 50 N/m is displaced by a force of 40 N. What is the displacement of the spring? (Fₛ = k Δx)

Answer 1

The spring stretches or compresses 0.8 m (80 cm)

Step-by-step explanation:

Hooke's Law

The force (F) needed to stretch or compress a spring by some distance Δx is given by

`F=-k\Delta x`

Where k is a constant factor characteristic of the spring.

We are given the constant of a spring k=50 N/m and it's required to calculate the displacement Δx produced by a force of F=40 N. Solving for Δx:

`\displaystyle \Delta x=(F)/(k)`

`\displaystyle \Delta x=(40)/(50)`

Calculating:

`\displaystyle \Delta x=0.8\ m`

The spring stretches or compresses 0.8 m (80 cm)