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Rectangle JKLM:J(-3, 8), K(-3,-1), L(4, -1),

M(4,8)
JK = 8 +1 -1=
KL=1-3+4 =​
Perimeter units?

User Saliu
by
8.5k points

1 Answer

3 votes

Answer:

The perimeter of the Rectangle JKLM is 32 unit.

Explanation:

Consider the provided coordinates.

Rectangle JKLM: J(-3, 8), K(-3,-1), L(4, -1), M(4,8)

First plot the points as shown in figure:

The required figure is shown below:

Now find the distance between JK by using the distance formula.


d=√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)


d=√(\left(-3-\left(-3\right)\right)^2+\left(-1-8\right)^2)=9

Therefore, the length of JK is 9 unit.

Now find the length of the side JM


d=√(\left(4-\left(-3\right)\right)^2+\left(8-8\right)^2)=7

Therefore, the length of JM is 7 unit.

The perimeter of rectangle is:
P=2(l+b)

Therefore,


P=2(7+9)


P=2(16)


P=32

Hence, the perimeter of the Rectangle JKLM is 32 unit.

Rectangle JKLM:J(-3, 8), K(-3,-1), L(4, -1), M(4,8) JK = 8 +1 -1= KL=1-3+4 =​ Perimeter-example-1
User Martinez
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